Sunday, March 22, 2015

Using Calipers/Micrometer to measure the density ofmetalcylinder;Determintion of an unknow mass

This Lad we try to handle two things, the first one is about the density, the other is about the unknow mass.
In this case, we measure three cylinders diameter and the height. The first one is copper. The second is steel. The last one is aluminum. In my date, i just set the code which is C, S , and O.
According my date, the height are 5cm+/-.01, 5cm+/-0.1, and 4.8cm+/-0.1, The mass are 58.5g, 62.0g, and 21.2g. The diameter are 1.25cm+/-0.1, 1.4cm+/-0.1, and 1.4cm+/-0.1, so we can know the radius are 0.625cm+/-0.05, 0.7cm+/-0.05, and 0.7cm+/-0.05.
As we know, density equal the mass over volume, ρ=m/s. So if we get each mass and volume, we will find the density. Then we get each density are 9.53*10^3kg/m^3, 8.05*10^3kg/m^3, and 2.869*10^3kg/m^3.
As this step, we use equation
we can find what the density will be changed if we change the mass, diameter, and height.
On the second experiment, we try to take some notes about the force and degree with the unknown mass. In the first picture, the F(1)left is 8N; the F(2)right is 6N; the theta(1)left is 48 degree and the theta(2)right is 24 degree.

On the second picture, the F(1) is 5N; the F(2) is 6025N; the theta(1) is 23 degree, and the theta(2) is 47 degree.


At the last, we find what the mass is and what the mass will be changed, when the two forces and angles change.



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