Today, we try to handle the problem about fall of an object falling with air resistance, at the first, the equation of resistance is that F(resistance)=kv^n.
This picture my partner and I just text the system. We take a video about the coffee filters, then set the length of the part of falling, and point the coffee filters allow time by time. Then the logger pro with the computer will calculate the function.
About these five function, we fallow our professor to go to the technology building and make the lab of falling objects. We take some videos and notes about the coffee filters which number are one, two, three, four, and five. Each filter's mass is 0.000926 kg. The acceleration is constant that is g=9.8m/s^2, Then there velocity should be same if there are friction-less about air. However, if we care about the friction about air, the velocity is different. According these picture, we know the velocity is 0.835m/s(one coffee filter), 0.1269m/s(two coffee filters), 0.1379m/s(3), 0.2080m/s(4), and 0.2320m/s(5).
Because the third experiment is a big eror, then we cancel that.
After we make the all experiments, we use logger pro to find the graph about the F(resistance). If we set the function Y=aX^b, Y is the F(resistance);X is the velocity; a is the k; b is the n.
As this graph, we know the k=1.338+/-0.09307, and the n=1.543+/-0.09163. (At this picture, we already calculate the mass to be the force.)
Then we set all case which we know and we find that the velocity and position is increasing but become slow; △v, △x and acceleration are decreasing and become to zero.
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