Projectile Motion

    On this case, we talk about the projectile motion with Newton's law.

The first picture shows us our lab and tools. in this step my partner should find the final velocity and the distance between the land point of ball and the table.

As the picture shows, we measure the theta which is 12 degree and the length is 0.79 meter, because the grav is 9.8m/s^2 and the mass of ball is 0.024kg, then the Fg is 0.2352N. then the F of ball is 0.2352*cos78, Because of F=ma, we know the acceleration is 2.04. then we know the t is 0.88s and the Vf is 1.6876m/s. (Allow the two function : Xf=Xi+Vi*t+1/2*a*t^2, and Xf=Xi+Vf*t-1/2*a*t^2.

As the second step, allow the same function, we know the time which the ball land, since the Vyi=0. The time is 0.4379s. and the Dx=0.65m, then the Vfinal =1.4814m/s.

at the second case, the every thing is same, so we need find the Distance.